Base | Representation |
---|---|
bin | 11010110011000001… |
… | …10010001100110101 |
3 | 1101010122001110211012 |
4 | 31121200302030311 |
5 | 213430441341331 |
6 | 10335324122005 |
7 | 1016341443323 |
oct | 153140621465 |
9 | 41118043735 |
10 | 14386668341 |
11 | 6112998951 |
12 | 2956096305 |
13 | 1483763306 |
14 | 9a69aad13 |
15 | 59306182b |
hex | 359832335 |
14386668341 has 2 divisors, whose sum is σ = 14386668342. Its totient is φ = 14386668340.
The previous prime is 14386668271. The next prime is 14386668367.
14386668341 is nontrivially palindromic in base 10.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13813065841 + 573602500 = 117529^2 + 23950^2 .
It is a palprime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14386668341 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14386668341.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14386668041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7193334170 + 7193334171.
It is an arithmetic number, because the mean of its divisors is an integer number (7193334171).
Almost surely, 214386668341 is an apocalyptic number.
It is an amenable number.
14386668341 is a deficient number, since it is larger than the sum of its proper divisors (1).
14386668341 is an equidigital number, since it uses as much as digits as its factorization.
14386668341 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1990656, while the sum is 50.
The spelling of 14386668341 in words is "fourteen billion, three hundred eighty-six million, six hundred sixty-eight thousand, three hundred forty-one".
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