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14387049113 is a prime number
BaseRepresentation
bin11010110011000100…
…01111001010011001
31101010122202211010212
431121202033022121
5213431041032423
610335340220505
71016344620413
oct153142171231
941118684125
1014387049113
116113128a38
12295623a735
131483867718
149a6a699b3
155930d9578
hex35988f299

14387049113 has 2 divisors, whose sum is σ = 14387049114. Its totient is φ = 14387049112.

The previous prime is 14387049107. The next prime is 14387049133. The reversal of 14387049113 is 31194078341.

14387049113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14247525769 + 139523344 = 119363^2 + 11812^2 .

It is a cyclic number.

It is not a de Polignac number, because 14387049113 - 26 = 14387049049 is a prime.

It is not a weakly prime, because it can be changed into another prime (14387049133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7193524556 + 7193524557.

It is an arithmetic number, because the mean of its divisors is an integer number (7193524557).

Almost surely, 214387049113 is an apocalyptic number.

It is an amenable number.

14387049113 is a deficient number, since it is larger than the sum of its proper divisors (1).

14387049113 is an equidigital number, since it uses as much as digits as its factorization.

14387049113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72576, while the sum is 41.

The spelling of 14387049113 in words is "fourteen billion, three hundred eighty-seven million, forty-nine thousand, one hundred thirteen".