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14392260220213 is a prime number
BaseRepresentation
bin1101000101101111010110…
…0011101101010100110101
31212221212221100201202212201
43101123311203231110311
53341300322104021323
650335414004544501
73013543424250661
oct321336543552465
955855840652781
1014392260220213
1146497a5763967
1217453969b2131
13805251c2c725
1437a8367438a1
1519e59809d8ad
hexd16f58ed535

14392260220213 has 2 divisors, whose sum is σ = 14392260220214. Its totient is φ = 14392260220212.

The previous prime is 14392260220183. The next prime is 14392260220229. The reversal of 14392260220213 is 31202206229341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12849514882884 + 1542745337329 = 3584622^2 + 1242073^2 .

It is a cyclic number.

It is not a de Polignac number, because 14392260220213 - 213 = 14392260212021 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14392260220253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7196130110106 + 7196130110107.

It is an arithmetic number, because the mean of its divisors is an integer number (7196130110107).

Almost surely, 214392260220213 is an apocalyptic number.

It is an amenable number.

14392260220213 is a deficient number, since it is larger than the sum of its proper divisors (1).

14392260220213 is an equidigital number, since it uses as much as digits as its factorization.

14392260220213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 62208, while the sum is 37.

Adding to 14392260220213 its reverse (31202206229341), we get a palindrome (45594466449554).

The spelling of 14392260220213 in words is "fourteen trillion, three hundred ninety-two billion, two hundred sixty million, two hundred twenty thousand, two hundred thirteen".