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143944037113 is a prime number
BaseRepresentation
bin1000011000001110111…
…0111011001011111001
3111202112201002201112211
42012003232323023321
54324244133141423
6150043232135121
713254032061532
oct2060356731371
9452481081484
10143944037113
1156056724648
1223a926974a1
131075ca1b176
146d77375689
153b270e010d
hex2183bbb2f9

143944037113 has 2 divisors, whose sum is σ = 143944037114. Its totient is φ = 143944037112.

The previous prime is 143944037077. The next prime is 143944037129. The reversal of 143944037113 is 311730449341.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 128786241424 + 15157795689 = 358868^2 + 123117^2 .

It is an emirp because it is prime and its reverse (311730449341) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-143944037113 is a prime.

It is not a weakly prime, because it can be changed into another prime (143944037143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71972018556 + 71972018557.

It is an arithmetic number, because the mean of its divisors is an integer number (71972018557).

Almost surely, 2143944037113 is an apocalyptic number.

It is an amenable number.

143944037113 is a deficient number, since it is larger than the sum of its proper divisors (1).

143944037113 is an equidigital number, since it uses as much as digits as its factorization.

143944037113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108864, while the sum is 40.

The spelling of 143944037113 in words is "one hundred forty-three billion, nine hundred forty-four million, thirty-seven thousand, one hundred thirteen".