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14400150083471 is a prime number
BaseRepresentation
bin1101000110001100101111…
…0101001001011110001111
31212222122022012220100120102
43101203023311021132033
53341413001410132341
650343200532041315
73014243100056525
oct321431365113617
955878265810512
1014400150083471
114652084346a09
121746a1916323b
13805c0b6c0179
1437ad8453c315
1519e8aaa90c9b
hexd18cbd4978f

14400150083471 has 2 divisors, whose sum is σ = 14400150083472. Its totient is φ = 14400150083470.

The previous prime is 14400150083467. The next prime is 14400150083603. The reversal of 14400150083471 is 17438005100441.

It is a weak prime.

It is an emirp because it is prime and its reverse (17438005100441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14400150083471 - 22 = 14400150083467 is a prime.

It is a super-3 number, since 3×144001500834713 (a number of 40 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14400150083461) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7200075041735 + 7200075041736.

It is an arithmetic number, because the mean of its divisors is an integer number (7200075041736).

Almost surely, 214400150083471 is an apocalyptic number.

14400150083471 is a deficient number, since it is larger than the sum of its proper divisors (1).

14400150083471 is an equidigital number, since it uses as much as digits as its factorization.

14400150083471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 53760, while the sum is 38.

The spelling of 14400150083471 in words is "fourteen trillion, four hundred billion, one hundred fifty million, eighty-three thousand, four hundred seventy-one".