144011313302117 has 2 divisors, whose sum is σ = 144011313302118. Its totient is φ = 144011313302116.

The previous prime is 144011313302107. The next prime is 144011313302141. The reversal of 144011313302117 is 711203313110441.

144011313302117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 132968711814436 + 11042601487681 = 11531206^2 + 3323041^2 .

It is a cyclic number.

It is not a de Polignac number, because 144011313302117 - 2⁴² = 139613266791013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (144011313302107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72005656651058 + 72005656651059.

It is an arithmetic number, because the mean of its divisors is an integer number (72005656651059).

Almost surely, 2^{144011313302117} is an apocalyptic number.

It is an amenable number.

144011313302117 is a deficient number, since it is larger than the sum of its proper divisors (1).

144011313302117 is an equidigital number, since it uses as much as digits as its factorization.

144011313302117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6048, while the sum is 32.

Adding to 144011313302117 its reverse (711203313110441), we get a palindrome (855214626412558).

The spelling of 144011313302117 in words is "one hundred forty-four trillion, eleven billion, three hundred thirteen million, three hundred two thousand, one hundred seventeen".