14401132422121 has 4 divisors (see below), whose sum is σ = 14402069218372. Its totient is φ = 14400195625872.

The previous prime is 14401132422107. The next prime is 14401132422161. The reversal of 14401132422121 is 12122423110441.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7489827930025 + 6911304492096 = 2736755^2 + 2628936^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14401132422121 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14401132422121.

It is not an unprimeable number, because it can be changed into a prime (14401132422161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 468375066 + ... + 468405811.

It is an arithmetic number, because the mean of its divisors is an integer number (3600517304593).

Almost surely, 2^{14401132422121} is an apocalyptic number.

It is an amenable number.

14401132422121 is a deficient number, since it is larger than the sum of its proper divisors (936796251).

14401132422121 is an equidigital number, since it uses as much as digits as its factorization.

14401132422121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 936796250.

The product of its (nonzero) digits is 3072, while the sum is 28.

Adding to 14401132422121 its reverse (12122423110441), we get a palindrome (26523555532562).

The spelling of 14401132422121 in words is "fourteen trillion, four hundred one billion, one hundred thirty-two million, four hundred twenty-two thousand, one hundred twenty-one".