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14401132422161 is a prime number
BaseRepresentation
bin1101000110010000011001…
…1000011110010000010001
31212222201211200100022220212
43101210012120132100101
53341422004400002121
650343442223013505
73014306325601652
oct321440630362021
955881750308825
1014401132422161
1146525388a7571
12174705213a295
13806037085574
1437b038bad529
1519e916e3425b
hexd190661e411

14401132422161 has 2 divisors, whose sum is σ = 14401132422162. Its totient is φ = 14401132422160.

The previous prime is 14401132422107. The next prime is 14401132422167. The reversal of 14401132422161 is 16122423110441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13629616132561 + 771516289600 = 3691831^2 + 878360^2 .

It is an emirp because it is prime and its reverse (16122423110441) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14401132422161 is a prime.

It is not a weakly prime, because it can be changed into another prime (14401132422167) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7200566211080 + 7200566211081.

It is an arithmetic number, because the mean of its divisors is an integer number (7200566211081).

Almost surely, 214401132422161 is an apocalyptic number.

It is an amenable number.

14401132422161 is a deficient number, since it is larger than the sum of its proper divisors (1).

14401132422161 is an equidigital number, since it uses as much as digits as its factorization.

14401132422161 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9216, while the sum is 32.

The spelling of 14401132422161 in words is "fourteen trillion, four hundred one billion, one hundred thirty-two million, four hundred twenty-two thousand, one hundred sixty-one".