1440120021331 has 2 divisors, whose sum is σ = 1440120021332. Its totient is φ = 1440120021330.

The previous prime is 1440120021313. The next prime is 1440120021337. The reversal of 1440120021331 is 1331200210441.

Together with previous prime (1440120021313) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1440120021331 - 2¹³ = 1440120013139 is a prime.

It is a super-2 number, since 2×1440120021331² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1440120021337) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 720060010665 + 720060010666.

It is an arithmetic number, because the mean of its divisors is an integer number (720060010666).

Almost surely, 2^{1440120021331} is an apocalyptic number.

1440120021331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1440120021331 is an equidigital number, since it uses as much as digits as its factorization.

1440120021331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 1440120021331 its reverse (1331200210441), we get a palindrome (2771320231772).

The spelling of 1440120021331 in words is "one trillion, four hundred forty billion, one hundred twenty million, twenty-one thousand, three hundred thirty-one".