1440120434233 has 4 divisors (see below), whose sum is σ = 1550898929188. Its totient is φ = 1329341939280.

The previous prime is 1440120434231. The next prime is 1440120434243. The reversal of 1440120434233 is 3324340210441.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 129651845184 + 1310468589049 = 360072^2 + 1144757^2 .

It is a cyclic number.

It is not a de Polignac number, because 1440120434233 - 2¹ = 1440120434231 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1440120434195 and 1440120434204.

It is not an unprimeable number, because it can be changed into a prime (1440120434231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55389247458 + ... + 55389247483.

It is an arithmetic number, because the mean of its divisors is an integer number (387724732297).

Almost surely, 2^{1440120434233} is an apocalyptic number.

1440120434233 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1440120434233 is a deficient number, since it is larger than the sum of its proper divisors (110778494955).

1440120434233 is a wasteful number, since it uses less digits than its factorization.

1440120434233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 110778494954.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 1440120434233 its reverse (3324340210441), we get a palindrome (4764460644674).

The spelling of 1440120434233 in words is "one trillion, four hundred forty billion, one hundred twenty million, four hundred thirty-four thousand, two hundred thirty-three".