Search a number
-
+
14401211311 = 59924042089
BaseRepresentation
bin11010110100110000…
…10000101110101111
31101011122102100000201
431122120100232233
5213443202230221
610341003534331
71016606163544
oct153230205657
941148370021
1014401211311
116120121233
12295ab2a3a7
131486785916
149a88b4bcb
15594485891
hex35a610baf

14401211311 has 4 divisors (see below), whose sum is σ = 14425254000. Its totient is φ = 14377168624.

The previous prime is 14401211303. The next prime is 14401211317. The reversal of 14401211311 is 11311210441.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14401211311 - 23 = 14401211303 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14401211317) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12020446 + ... + 12021643.

It is an arithmetic number, because the mean of its divisors is an integer number (3606313500).

Almost surely, 214401211311 is an apocalyptic number.

14401211311 is a deficient number, since it is larger than the sum of its proper divisors (24042689).

14401211311 is an equidigital number, since it uses as much as digits as its factorization.

14401211311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24042688.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 14401211311 its reverse (11311210441), we get a palindrome (25712421752).

The spelling of 14401211311 in words is "fourteen billion, four hundred one million, two hundred eleven thousand, three hundred eleven".

Divisors: 1 599 24042089 14401211311