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14401211344427 is a prime number
BaseRepresentation
bin1101000110010000101100…
…0101100010011000101011
31212222202001011211222220202
43101210023011202120223
53341422140101010202
650343454122342415
73014311304456015
oct321441305423053
955882034758822
1014401211344427
114652579401a86
12174707465aa0b
1380604a52922b
1437b0454751b5
1519e91dd23802
hexd190b16262b

14401211344427 has 2 divisors, whose sum is σ = 14401211344428. Its totient is φ = 14401211344426.

The previous prime is 14401211344393. The next prime is 14401211344451. The reversal of 14401211344427 is 72444311210441.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14401211344427 - 216 = 14401211278891 is a prime.

It is not a weakly prime, because it can be changed into another prime (14401211344127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7200605672213 + 7200605672214.

It is an arithmetic number, because the mean of its divisors is an integer number (7200605672214).

Almost surely, 214401211344427 is an apocalyptic number.

14401211344427 is a deficient number, since it is larger than the sum of its proper divisors (1).

14401211344427 is an equidigital number, since it uses as much as digits as its factorization.

14401211344427 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 86016, while the sum is 38.

Adding to 14401211344427 its reverse (72444311210441), we get a palindrome (86845522554868).

The spelling of 14401211344427 in words is "fourteen trillion, four hundred one billion, two hundred eleven million, three hundred forty-four thousand, four hundred twenty-seven".