14401211344451 has 2 divisors, whose sum is σ = 14401211344452. Its totient is φ = 14401211344450.

The previous prime is 14401211344427. The next prime is 14401211344483. The reversal of 14401211344451 is 15444311210441.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14401211344451 - 2²² = 14401207150147 is a prime.

It is not a weakly prime, because it can be changed into another prime (14401211544451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7200605672225 + 7200605672226.

It is an arithmetic number, because the mean of its divisors is an integer number (7200605672226).

Almost surely, 2^{14401211344451} is an apocalyptic number.

14401211344451 is a deficient number, since it is larger than the sum of its proper divisors (1).

14401211344451 is an equidigital number, since it uses as much as digits as its factorization.

14401211344451 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30720, while the sum is 35.

Adding to 14401211344451 its reverse (15444311210441), we get a palindrome (29845522554892).

The spelling of 14401211344451 in words is "fourteen trillion, four hundred one billion, two hundred eleven million, three hundred forty-four thousand, four hundred fifty-one".