144012114121 has 2 divisors, whose sum is σ = 144012114122. Its totient is φ = 144012114120.

The previous prime is 144012114109. The next prime is 144012114143. The reversal of 144012114121 is 121411210441.

It is an a-pointer prime, because the next prime (144012114143) can be obtained adding 144012114121 to its sum of digits (22).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 140801305225 + 3210808896 = 375235^2 + 56664^2 .

It is a cyclic number.

It is not a de Polignac number, because 144012114121 - 2⁵ = 144012114089 is a prime.

It is a super-3 number, since 3×144012114121³ (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 144012114092 and 144012114101.

It is not a weakly prime, because it can be changed into another prime (144012144121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72006057060 + 72006057061.

It is an arithmetic number, because the mean of its divisors is an integer number (72006057061).

Almost surely, 2^144012114121 is an apocalyptic number.

It is an amenable number.

144012114121 is a deficient number, since it is larger than the sum of its proper divisors (1).

144012114121 is an equidigital number, since it uses as much as digits as its factorization.

144012114121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 256, while the sum is 22.

Adding to 144012114121 its reverse (121411210441), we get a palindrome (265423324562).

The spelling of 144012114121 in words is "one hundred forty-four billion, twelve million, one hundred fourteen thousand, one hundred twenty-one".