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14401301345423 = 97431478117761
BaseRepresentation
bin1101000110010001000001…
…1100110111010010001111
31212222202021110012112001222
43101210100130313102033
53341422331121023143
650343511055353555
73014313446454416
oct321442034672217
955882243175058
1014401301345423
114652615194073
12174709a8228bb
1380606307b765
1437b0533c247d
1519e926ba0768
hexd191073748f

14401301345423 has 4 divisors (see below), whose sum is σ = 14402779472928. Its totient is φ = 14399823217920.

The previous prime is 14401301345401. The next prime is 14401301345449. The reversal of 14401301345423 is 32454310310441.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14401301345423 - 236 = 14332581868687 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14401301345323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 739049138 + ... + 739068623.

It is an arithmetic number, because the mean of its divisors is an integer number (3600694868232).

Almost surely, 214401301345423 is an apocalyptic number.

14401301345423 is a deficient number, since it is larger than the sum of its proper divisors (1478127505).

14401301345423 is an equidigital number, since it uses as much as digits as its factorization.

14401301345423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1478127504.

The product of its (nonzero) digits is 69120, while the sum is 35.

Adding to 14401301345423 its reverse (32454310310441), we get a palindrome (46855611655864).

The spelling of 14401301345423 in words is "fourteen trillion, four hundred one billion, three hundred one million, three hundred forty-five thousand, four hundred twenty-three".

Divisors: 1 9743 1478117761 14401301345423