14402113010101 has 4 divisors (see below), whose sum is σ = 14402169696172. Its totient is φ = 14402056324032.

The previous prime is 14402113010093. The next prime is 14402113010111. The reversal of 14402113010101 is 10101031120441.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8606302322500 + 5795810687601 = 2933650^2 + 2407449^2 .

It is a cyclic number.

It is not a de Polignac number, because 14402113010101 - 2³ = 14402113010093 is a prime.

It is a super-3 number, since 3×14402113010101³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14402113010111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27960210 + ... + 28470643.

It is an arithmetic number, because the mean of its divisors is an integer number (3600542424043).

Almost surely, 2^{14402113010101} is an apocalyptic number.

It is an amenable number.

14402113010101 is a deficient number, since it is larger than the sum of its proper divisors (56686071).

14402113010101 is an equidigital number, since it uses as much as digits as its factorization.

14402113010101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56686070.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 14402113010101 its reverse (10101031120441), we get a palindrome (24503144130542).

The spelling of 14402113010101 in words is "fourteen trillion, four hundred two billion, one hundred thirteen million, ten thousand, one hundred one".