Base | Representation |
---|---|
bin | 11010110100111001… |
… | …10110011110000111 |
3 | 1101011201200110110012 |
4 | 31122130312132013 |
5 | 213444004230341 |
6 | 10341045420435 |
7 | 1016622334364 |
oct | 153234663607 |
9 | 41151613405 |
10 | 14402414471 |
11 | 6120873185 |
12 | 295b40a71b |
13 | 1486ab7453 |
14 | 9a8b0946b |
15 | 5946220eb |
hex | 35a736787 |
14402414471 has 2 divisors, whose sum is σ = 14402414472. Its totient is φ = 14402414470.
The previous prime is 14402414423. The next prime is 14402414483. The reversal of 14402414471 is 17441420441.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14402414471 is a prime.
It is a super-3 number, since 3×144024144713 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14402414171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7201207235 + 7201207236.
It is an arithmetic number, because the mean of its divisors is an integer number (7201207236).
Almost surely, 214402414471 is an apocalyptic number.
14402414471 is a deficient number, since it is larger than the sum of its proper divisors (1).
14402414471 is an equidigital number, since it uses as much as digits as its factorization.
14402414471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14336, while the sum is 32.
The spelling of 14402414471 in words is "fourteen billion, four hundred two million, four hundred fourteen thousand, four hundred seventy-one".
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