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14403310423 = 61331713353
BaseRepresentation
bin11010110101000000…
…10001001101010111
31101011210100222110121
431122200101031113
5213444221413143
610341120532411
71016633055445
oct153240211527
941153328417
1014403310423
116121325337
12295b781107
13148703c1b8
149a8c9db95
1559474c7ed
hex35a811357

14403310423 has 8 divisors (see below), whose sum is σ = 14683678736. Its totient is φ = 14124369600.

The previous prime is 14403310409. The next prime is 14403310459. The reversal of 14403310423 is 32401330441.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14403310423 - 25 = 14403310391 is a prime.

It is a super-2 number, since 2×144033104232 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14403310403) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 336486 + ... + 376867.

It is an arithmetic number, because the mean of its divisors is an integer number (1835459842).

Almost surely, 214403310423 is an apocalyptic number.

14403310423 is a deficient number, since it is larger than the sum of its proper divisors (280368313).

14403310423 is an equidigital number, since it uses as much as digits as its factorization.

14403310423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 713745.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 14403310423 its reverse (32401330441), we get a palindrome (46804640864).

The spelling of 14403310423 in words is "fourteen billion, four hundred three million, three hundred ten thousand, four hundred twenty-three".

Divisors: 1 61 331 20191 713353 43514533 236119843 14403310423