Base | Representation |
---|---|
bin | 10100111101011010011… |
… | …111000101000111010011 |
3 | 12002200202020000211210021 |
4 | 110331122133011013103 |
5 | 142044300012003021 |
6 | 3021402432244311 |
7 | 206026526124001 |
oct | 24753237050723 |
9 | 5080666024707 |
10 | 1440332141011 |
11 | 505928a42835 |
12 | 1b31903a0697 |
13 | a5a9072b87a |
14 | 4d9d8d55a71 |
15 | 276edda3c41 |
hex | 14f5a7c51d3 |
1440332141011 has 8 divisors (see below), whose sum is σ = 1479276195264. Its totient is φ = 1401388937280.
The previous prime is 1440332140931. The next prime is 1440332141057. The reversal of 1440332141011 is 1101412330441.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1440332141011 - 217 = 1440332009939 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1440332141111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4789551 + ... + 5081383.
It is an arithmetic number, because the mean of its divisors is an integer number (184909524408).
Almost surely, 21440332141011 is an apocalyptic number.
1440332141011 is a deficient number, since it is larger than the sum of its proper divisors (38944054253).
1440332141011 is a wasteful number, since it uses less digits than its factorization.
1440332141011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 425261.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1440332141011 its reverse (1101412330441), we get a palindrome (2541744471452).
The spelling of 1440332141011 in words is "one trillion, four hundred forty billion, three hundred thirty-two million, one hundred forty-one thousand, eleven".
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