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144033400051 is a prime number
BaseRepresentation
bin1000011000100100001…
…1110100010011110011
3111202202221020211110021
42012021003310103303
54324440022300201
6150100143344311
713256165462062
oct2061103642363
9452687224407
10144033400051
11560a2110312
1223ab85b2097
13107753a9148
146d851981d9
153b2ed92ea1
hex21890f44f3

144033400051 has 2 divisors, whose sum is σ = 144033400052. Its totient is φ = 144033400050.

The previous prime is 144033400009. The next prime is 144033400097. The reversal of 144033400051 is 150004330441.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-144033400051 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 144033399989 and 144033400025.

It is not a weakly prime, because it can be changed into another prime (144033404051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72016700025 + 72016700026.

It is an arithmetic number, because the mean of its divisors is an integer number (72016700026).

Almost surely, 2144033400051 is an apocalyptic number.

144033400051 is a deficient number, since it is larger than the sum of its proper divisors (1).

144033400051 is an equidigital number, since it uses as much as digits as its factorization.

144033400051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 144033400051 its reverse (150004330441), we get a palindrome (294037730492).

The spelling of 144033400051 in words is "one hundred forty-four billion, thirty-three million, four hundred thousand, fifty-one".