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144034001201533 is a prime number
BaseRepresentation
bin100000101111111110000111…
…011110100010100101111101
3200212222111221012012020112211
4200233332013132202211331
5122334323113301422113
61230200150124500421
742224053551530512
oct4057760736424575
9625874835166484
10144034001201533
11419915277a0873
12141a29076aa711
13624a46a8237a1
14277d3d621d309
15119b9c54d1b3d
hex82ff877a297d

144034001201533 has 2 divisors, whose sum is σ = 144034001201534. Its totient is φ = 144034001201532.

The previous prime is 144034001201477. The next prime is 144034001201539. The reversal of 144034001201533 is 335102100430441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 98817158625124 + 45216842576409 = 9940682^2 + 6724347^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-144034001201533 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 144034001201495 and 144034001201504.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (144034001201539) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72017000600766 + 72017000600767.

It is an arithmetic number, because the mean of its divisors is an integer number (72017000600767).

Almost surely, 2144034001201533 is an apocalyptic number.

It is an amenable number.

144034001201533 is a deficient number, since it is larger than the sum of its proper divisors (1).

144034001201533 is an equidigital number, since it uses as much as digits as its factorization.

144034001201533 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 144034001201533 its reverse (335102100430441), we get a palindrome (479136101631974).

The spelling of 144034001201533 in words is "one hundred forty-four trillion, thirty-four billion, one million, two hundred one thousand, five hundred thirty-three".