Base | Representation |
---|---|
bin | 1101000110011000110110… |
… | …0110111100101110011011 |
3 | 1212222221200210100012021222 |
4 | 3101212031212330232123 |
5 | 3341441131143004042 |
6 | 50344455305322255 |
7 | 3014416464441014 |
oct | 321461546745633 |
9 | 55887623305258 |
10 | 14403401141147 |
11 | 46534a24a2737 |
12 | 1747585a9638b |
13 | 8063090c7635 |
14 | 37b1b221800b |
15 | 19e9eb1c72d2 |
hex | d198d9bcb9b |
14403401141147 has 2 divisors, whose sum is σ = 14403401141148. Its totient is φ = 14403401141146.
The previous prime is 14403401141117. The next prime is 14403401141161. The reversal of 14403401141147 is 74114110430441.
It is a strong prime.
It is an emirp because it is prime and its reverse (74114110430441) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14403401141147 - 212 = 14403401137051 is a prime.
It is not a weakly prime, because it can be changed into another prime (14403401141117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7201700570573 + 7201700570574.
It is an arithmetic number, because the mean of its divisors is an integer number (7201700570574).
Almost surely, 214403401141147 is an apocalyptic number.
14403401141147 is a deficient number, since it is larger than the sum of its proper divisors (1).
14403401141147 is an equidigital number, since it uses as much as digits as its factorization.
14403401141147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21504, while the sum is 35.
Adding to 14403401141147 its reverse (74114110430441), we get a palindrome (88517511571588).
The spelling of 14403401141147 in words is "fourteen trillion, four hundred three billion, four hundred one million, one hundred forty-one thousand, one hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •