Base | Representation |
---|---|
bin | 1101000110011000110110… |
… | …0110111100101101111101 |
3 | 1212222221200210100012020212 |
4 | 3101212031212330231331 |
5 | 3341441131143003432 |
6 | 50344455305322205 |
7 | 3014416464440642 |
oct | 321461546745575 |
9 | 55887623305225 |
10 | 14403401141117 |
11 | 46534a24a270a |
12 | 1747585a96365 |
13 | 8063090c7611 |
14 | 37b1b2217dc9 |
15 | 19e9eb1c72b2 |
hex | d198d9bcb7d |
14403401141117 has 2 divisors, whose sum is σ = 14403401141118. Its totient is φ = 14403401141116.
The previous prime is 14403401140951. The next prime is 14403401141147. The reversal of 14403401141117 is 71114110430441.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13469406464761 + 933994676356 = 3670069^2 + 966434^2 .
It is a cyclic number.
It is not a de Polignac number, because 14403401141117 - 28 = 14403401140861 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14403401141147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7201700570558 + 7201700570559.
It is an arithmetic number, because the mean of its divisors is an integer number (7201700570559).
Almost surely, 214403401141117 is an apocalyptic number.
It is an amenable number.
14403401141117 is a deficient number, since it is larger than the sum of its proper divisors (1).
14403401141117 is an equidigital number, since it uses as much as digits as its factorization.
14403401141117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5376, while the sum is 32.
Adding to 14403401141117 its reverse (71114110430441), we get a palindrome (85517511571558).
The spelling of 14403401141117 in words is "fourteen trillion, four hundred three billion, four hundred one million, one hundred forty-one thousand, one hundred seventeen".
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