Base | Representation |
---|---|
bin | 1101000110011000111001… |
… | …0001100101111100101111 |
3 | 1212222221201120101010212022 |
4 | 3101212032101211330233 |
5 | 3341441142023220142 |
6 | 50344500345100355 |
7 | 3014416661450402 |
oct | 321461621457457 |
9 | 55887646333768 |
10 | 14403412320047 |
11 | 46534a88385a3 |
12 | 17475897876bb |
13 | 80630b50c97a |
14 | 37b1b38c7d39 |
15 | 19e9ec1846d2 |
hex | d198e465f2f |
14403412320047 has 2 divisors, whose sum is σ = 14403412320048. Its totient is φ = 14403412320046.
The previous prime is 14403412319993. The next prime is 14403412320083. The reversal of 14403412320047 is 74002321430441.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14403412320047 - 226 = 14403345211183 is a prime.
It is a super-2 number, since 2×144034123200472 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14403412319989 and 14403412320016.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14403412328047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7201706160023 + 7201706160024.
It is an arithmetic number, because the mean of its divisors is an integer number (7201706160024).
Almost surely, 214403412320047 is an apocalyptic number.
14403412320047 is a deficient number, since it is larger than the sum of its proper divisors (1).
14403412320047 is an equidigital number, since it uses as much as digits as its factorization.
14403412320047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64512, while the sum is 35.
Adding to 14403412320047 its reverse (74002321430441), we get a palindrome (88405733750488).
The spelling of 14403412320047 in words is "fourteen trillion, four hundred three billion, four hundred twelve million, three hundred twenty thousand, forty-seven".
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