14403420131 has 4 divisors (see below), whose sum is σ = 14404222200. Its totient is φ = 14402618064.

The previous prime is 14403420049. The next prime is 14403420133. The reversal of 14403420131 is 13102430441.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13102430441 = 199 ⋅65841359.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14403420131 is a prime.

It is a super-2 number, since 2×14403420131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14403420097 and 14403420106.

It is not an unprimeable number, because it can be changed into a prime (14403420133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 373466 + ... + 410223.

It is an arithmetic number, because the mean of its divisors is an integer number (3601055550).

Almost surely, 2^14403420131 is an apocalyptic number.

14403420131 is a deficient number, since it is larger than the sum of its proper divisors (802069).

14403420131 is an equidigital number, since it uses as much as digits as its factorization.

14403420131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 802068.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 14403420131 its reverse (13102430441), we get a palindrome (27505850572).

The spelling of 14403420131 in words is "fourteen billion, four hundred three million, four hundred twenty thousand, one hundred thirty-one".