Base | Representation |
---|---|
bin | 100000101111111110010101… |
… | …101110010111011011000111 |
3 | 200212222112112211222012111011 |
4 | 200233332111232113123013 |
5 | 122334324110444343421 |
6 | 1230200225544023051 |
7 | 42224062513331656 |
oct | 4057762556273307 |
9 | 625875484865434 |
10 | 144034240231111 |
11 | 4199163a71127a |
12 | 141a2973761a87 |
13 | 624a4a81c49c9 |
14 | 277d419c8119d |
15 | 119b9db49a4e1 |
hex | 82ff95b976c7 |
144034240231111 has 2 divisors, whose sum is σ = 144034240231112. Its totient is φ = 144034240231110.
The previous prime is 144034240231033. The next prime is 144034240231151. The reversal of 144034240231111 is 111132042430441.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 144034240231111 - 27 = 144034240230983 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (144034240231151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72017120115555 + 72017120115556.
It is an arithmetic number, because the mean of its divisors is an integer number (72017120115556).
Almost surely, 2144034240231111 is an apocalyptic number.
144034240231111 is a deficient number, since it is larger than the sum of its proper divisors (1).
144034240231111 is an equidigital number, since it uses as much as digits as its factorization.
144034240231111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9216, while the sum is 31.
Adding to 144034240231111 its reverse (111132042430441), we get a palindrome (255166282661552).
The spelling of 144034240231111 in words is "one hundred forty-four trillion, thirty-four billion, two hundred forty million, two hundred thirty-one thousand, one hundred eleven".
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