Base | Representation |
---|---|
bin | 1000011000100100011… |
… | …1010111101010100110 |
3 | 111202210000000010220001 |
4 | 2012021013113222212 |
5 | 4324440242100202 |
6 | 150100215331514 |
7 | 13256206421101 |
oct | 2061107275246 |
9 | 452700003801 |
10 | 144034331302 |
11 | 560a2696a44 |
12 | 23ab8980b9a |
13 | 10775643c94 |
14 | 6d8535b738 |
15 | 3b2eec8d87 |
hex | 21891d7aa6 |
144034331302 has 4 divisors (see below), whose sum is σ = 216051496956. Its totient is φ = 72017165650.
The previous prime is 144034331299. The next prime is 144034331317. The reversal of 144034331302 is 203133430441.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 203133430441 = 59 ⋅3442939499.
It is a super-2 number, since 2×1440343313022 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 36008582824 + ... + 36008582827.
It is an arithmetic number, because the mean of its divisors is an integer number (54012874239).
Almost surely, 2144034331302 is an apocalyptic number.
144034331302 is a deficient number, since it is larger than the sum of its proper divisors (72017165654).
144034331302 is an equidigital number, since it uses as much as digits as its factorization.
144034331302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 72017165653.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 144034331302 its reverse (203133430441), we get a palindrome (347167761743).
The spelling of 144034331302 in words is "one hundred forty-four billion, thirty-four million, three hundred thirty-one thousand, three hundred two".
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