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14403523403207 = 19937227056399
BaseRepresentation
bin1101000110011001010011…
…1001010101110111000111
31212222222000022101202022102
43101212110321111313013
53341441403442400312
650344515354022315
73014422510603121
oct321462471256707
955888008352272
1014403523403207
114653555509a64
1217475baa1799b
13806328534053
1437b1c4562211
1519ea06cc7ec2
hexd1994e55dc7

14403523403207 has 4 divisors (see below), whose sum is σ = 14410750461600. Its totient is φ = 14396296344816.

The previous prime is 14403523403179. The next prime is 14403523403209. The reversal of 14403523403207 is 70230432530441.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14403523403207 is a prime.

It is a super-2 number, since 2×144035234032072 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14403523403209) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3613526207 + ... + 3613530192.

It is an arithmetic number, because the mean of its divisors is an integer number (3602687615400).

Almost surely, 214403523403207 is an apocalyptic number.

14403523403207 is a deficient number, since it is larger than the sum of its proper divisors (7227058393).

14403523403207 is an equidigital number, since it uses as much as digits as its factorization.

14403523403207 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7227058392.

The product of its (nonzero) digits is 241920, while the sum is 38.

Adding to 14403523403207 its reverse (70230432530441), we get a palindrome (84633955933648).

The spelling of 14403523403207 in words is "fourteen trillion, four hundred three billion, five hundred twenty-three million, four hundred three thousand, two hundred seven".

Divisors: 1 1993 7227056399 14403523403207