14404000213 has 4 divisors (see below), whose sum is σ = 14407856320. Its totient is φ = 14400144108.

The previous prime is 14404000181. The next prime is 14404000231. The reversal of 14404000213 is 31200040441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31200040441 = 107 ⋅291589163.

It is a cyclic number.

It is not a de Polignac number, because 14404000213 - 2⁵ = 14404000181 is a prime.

It is a super-2 number, since 2×14404000213² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14404000283) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1922445 + ... + 1929922.

It is an arithmetic number, because the mean of its divisors is an integer number (3601964080).

Almost surely, 2^14404000213 is an apocalyptic number.

It is an amenable number.

14404000213 is a deficient number, since it is larger than the sum of its proper divisors (3856107).

14404000213 is an equidigital number, since it uses as much as digits as its factorization.

14404000213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3856106.

The product of its (nonzero) digits is 384, while the sum is 19.

Adding to 14404000213 its reverse (31200040441), we get a palindrome (45604040654).

The spelling of 14404000213 in words is "fourteen billion, four hundred four million, two hundred thirteen", and thus it is an aban number.