Base | Representation |
---|---|
bin | 100000110000000011101110… |
… | …010010110000000000111011 |
3 | 200220000002110201202100202102 |
4 | 200300003232102300000323 |
5 | 122334422430402200243 |
6 | 1230203023332454015 |
7 | 42224356000223312 |
oct | 4060035622600073 |
9 | 626002421670672 |
10 | 144040021131323 |
11 | 419940368a4159 |
12 | 141a3b0777a30b |
13 | 624abb9a79a15 |
14 | 277d807939279 |
15 | 119bc28c549b8 |
hex | 8300ee4b003b |
144040021131323 has 4 divisors (see below), whose sum is σ = 144042138158568. Its totient is φ = 144037904104080.
The previous prime is 144040021131263. The next prime is 144040021131353. The reversal of 144040021131323 is 323131120040441.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 144040021131323 - 212 = 144040021127227 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (144040021131353) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1058411561 + ... + 1058547642.
It is an arithmetic number, because the mean of its divisors is an integer number (36010534539642).
Almost surely, 2144040021131323 is an apocalyptic number.
144040021131323 is a deficient number, since it is larger than the sum of its proper divisors (2117027245).
144040021131323 is an equidigital number, since it uses as much as digits as its factorization.
144040021131323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2117027244.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 144040021131323 its reverse (323131120040441), we get a palindrome (467171141171764).
The spelling of 144040021131323 in words is "one hundred forty-four trillion, forty billion, twenty-one million, one hundred thirty-one thousand, three hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •