144040021131353 has 2 divisors, whose sum is σ = 144040021131354. Its totient is φ = 144040021131352.

The previous prime is 144040021131263. The next prime is 144040021131431. The reversal of 144040021131353 is 353131120040441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113439796259344 + 30600224872009 = 10650812^2 + 5531747^2 .

It is a cyclic number.

It is not a de Polignac number, because 144040021131353 - 2¹⁸ = 144040020869209 is a prime.

It is a super-2 number, since 2×144040021131353² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (144040021134353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72020010565676 + 72020010565677.

It is an arithmetic number, because the mean of its divisors is an integer number (72020010565677).

Almost surely, 2^{144040021131353} is an apocalyptic number.

It is an amenable number.

144040021131353 is a deficient number, since it is larger than the sum of its proper divisors (1).

144040021131353 is an equidigital number, since it uses as much as digits as its factorization.

144040021131353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 144040021131353 its reverse (353131120040441), we get a palindrome (497171141171794).

The spelling of 144040021131353 in words is "one hundred forty-four trillion, forty billion, twenty-one million, one hundred thirty-one thousand, three hundred fifty-three".