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14404025055503 = 53580674680353
BaseRepresentation
bin1101000110011011001011…
…0010111111100100001111
31220000000022021100022220002
43101212302302333210033
53341443420403234003
650345041234114515
73014441111561216
oct321466262774417
956000267308802
1014404025055503
1146537926a4836
12174771aa1ba3b
138063a8447225
1437b23102807d
1519ea35d6aa88
hexd19b2cbf90f

14404025055503 has 8 divisors (see below), whose sum is σ = 14676054987888. Its totient is φ = 14132004600064.

The previous prime is 14404025055499. The next prime is 14404025055559. The reversal of 14404025055503 is 30555052040441.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14404025055503 - 22 = 14404025055499 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14404025055103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 737375 + ... + 5417727.

It is an arithmetic number, because the mean of its divisors is an integer number (1834506873486).

Almost surely, 214404025055503 is an apocalyptic number.

14404025055503 is a deficient number, since it is larger than the sum of its proper divisors (272029932385).

14404025055503 is an equidigital number, since it uses as much as digits as its factorization.

14404025055503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4738473.

The product of its (nonzero) digits is 240000, while the sum is 38.

Adding to 14404025055503 its reverse (30555052040441), we get a palindrome (44959077095944).

The spelling of 14404025055503 in words is "fourteen trillion, four hundred four billion, twenty-five million, fifty-five thousand, five hundred three".

Divisors: 1 53 58067 3077551 4680353 248058709 271774057651 14404025055503