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14404387342753 is a prime number
BaseRepresentation
bin1101000110011100100001…
…1001000000100110100001
31220000001020112001102120101
43101213020121000212201
53342000141124432003
650345141215142401
73014453101142242
oct321471031004641
956001215042511
1014404387342753
114653959151591
121747800214a01
13806435513095
1437b2671b2cc9
1519ea57a8011d
hexd19c86409a1

14404387342753 has 2 divisors, whose sum is σ = 14404387342754. Its totient is φ = 14404387342752.

The previous prime is 14404387342729. The next prime is 14404387342757. The reversal of 14404387342753 is 35724378340441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14306375770129 + 98011572624 = 3782377^2 + 313068^2 .

It is a cyclic number.

It is not a de Polignac number, because 14404387342753 - 217 = 14404387211681 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14404387342694 and 14404387342703.

It is not a weakly prime, because it can be changed into another prime (14404387342757) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7202193671376 + 7202193671377.

It is an arithmetic number, because the mean of its divisors is an integer number (7202193671377).

Almost surely, 214404387342753 is an apocalyptic number.

It is an amenable number.

14404387342753 is a deficient number, since it is larger than the sum of its proper divisors (1).

14404387342753 is an equidigital number, since it uses as much as digits as its factorization.

14404387342753 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27095040, while the sum is 55.

The spelling of 14404387342753 in words is "fourteen trillion, four hundred four billion, three hundred eighty-seven million, three hundred forty-two thousand, seven hundred fifty-three".