Base | Representation |
---|---|
bin | 10100111101100100100… |
… | …100111010000000100111 |
3 | 12002201012000121011002121 |
4 | 110331210210322000213 |
5 | 142100121332044201 |
6 | 3021431321050411 |
7 | 206033653134445 |
oct | 24754444720047 |
9 | 5081160534077 |
10 | 1440501440551 |
11 | 505a05567008 |
12 | 1b3219026a07 |
13 | a5ab9827104 |
14 | 4da13625b95 |
15 | 2770db969a1 |
hex | 14f6493a027 |
1440501440551 has 2 divisors, whose sum is σ = 1440501440552. Its totient is φ = 1440501440550.
The previous prime is 1440501440531. The next prime is 1440501440563. The reversal of 1440501440551 is 1550441050441.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1440501440551 - 225 = 1440467886119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1440501440531) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 720250720275 + 720250720276.
It is an arithmetic number, because the mean of its divisors is an integer number (720250720276).
Almost surely, 21440501440551 is an apocalyptic number.
1440501440551 is a deficient number, since it is larger than the sum of its proper divisors (1).
1440501440551 is an equidigital number, since it uses as much as digits as its factorization.
1440501440551 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32000, while the sum is 34.
Adding to 1440501440551 its reverse (1550441050441), we get a palindrome (2990942490992).
The spelling of 1440501440551 in words is "one trillion, four hundred forty billion, five hundred one million, four hundred forty thousand, five hundred fifty-one".
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