Base | Representation |
---|---|
bin | 1000011000110100011… |
… | …0111000011110101111 |
3 | 111202221200001010201121 |
4 | 2012031012320132233 |
5 | 4330104413444211 |
6 | 150111011121411 |
7 | 13260651642256 |
oct | 2061506703657 |
9 | 452850033647 |
10 | 144101312431 |
11 | 5612748594a |
12 | 23b172a3267 |
13 | 1078649669b |
14 | 6d901d579d |
15 | 3b35d0a271 |
hex | 218d1b87af |
144101312431 has 2 divisors, whose sum is σ = 144101312432. Its totient is φ = 144101312430.
The previous prime is 144101312393. The next prime is 144101312441. The reversal of 144101312431 is 134213101441.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 144101312431 - 29 = 144101311919 is a prime.
It is a super-2 number, since 2×1441013124312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 144101312396 and 144101312405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (144101312441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72050656215 + 72050656216.
It is an arithmetic number, because the mean of its divisors is an integer number (72050656216).
Almost surely, 2144101312431 is an apocalyptic number.
144101312431 is a deficient number, since it is larger than the sum of its proper divisors (1).
144101312431 is an equidigital number, since it uses as much as digits as its factorization.
144101312431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 144101312431 its reverse (134213101441), we get a palindrome (278314413872).
The spelling of 144101312431 in words is "one hundred forty-four billion, one hundred one million, three hundred twelve thousand, four hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •