Base | Representation |
---|---|
bin | 1101000110110010010000… |
… | …0111000100111101110001 |
3 | 1220000121022002022200011112 |
4 | 3101230210013010331301 |
5 | 3342044113101110301 |
6 | 50351544133123105 |
7 | 3015050466314324 |
oct | 321544407047561 |
9 | 56017262280145 |
10 | 14410221113201 |
11 | 4656382165681 |
12 | 1748969a89495 |
13 | 806b55019a64 |
14 | 37b65bcb07bb |
15 | 19ec99cce9bb |
hex | d1b241c4f71 |
14410221113201 has 2 divisors, whose sum is σ = 14410221113202. Its totient is φ = 14410221113200.
The previous prime is 14410221113083. The next prime is 14410221113219. The reversal of 14410221113201 is 10231112201441.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8031692032576 + 6378529080625 = 2834024^2 + 2525575^2 .
It is a cyclic number.
It is not a de Polignac number, because 14410221113201 - 242 = 10012174602097 is a prime.
It is not a weakly prime, because it can be changed into another prime (14410221113261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7205110556600 + 7205110556601.
It is an arithmetic number, because the mean of its divisors is an integer number (7205110556601).
Almost surely, 214410221113201 is an apocalyptic number.
It is an amenable number.
14410221113201 is a deficient number, since it is larger than the sum of its proper divisors (1).
14410221113201 is an equidigital number, since it uses as much as digits as its factorization.
14410221113201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 14410221113201 its reverse (10231112201441), we get a palindrome (24641333314642).
The spelling of 14410221113201 in words is "fourteen trillion, four hundred ten billion, two hundred twenty-one million, one hundred thirteen thousand, two hundred one".
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