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1441034113 = 5924424307
BaseRepresentation
bin101010111100100…
…0110111110000001
310201102120010011211
41111321012332001
510422401042423
6354554210121
750465405431
oct12571067601
93642503154
101441034113
1167a476292
12342723941
1319c717c0c
14d95542c1
158679d10d
hex55e46f81

1441034113 has 4 divisors (see below), whose sum is σ = 1465458480. Its totient is φ = 1416609748.

The previous prime is 1441034107. The next prime is 1441034123. The reversal of 1441034113 is 3114301441.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1441034113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1441034123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12212095 + ... + 12212212.

It is an arithmetic number, because the mean of its divisors is an integer number (366364620).

Almost surely, 21441034113 is an apocalyptic number.

It is an amenable number.

1441034113 is a deficient number, since it is larger than the sum of its proper divisors (24424367).

1441034113 is an equidigital number, since it uses as much as digits as its factorization.

1441034113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24424366.

The product of its (nonzero) digits is 576, while the sum is 22.

The square root of 1441034113 is about 37960.9551117988. The cubic root of 1441034113 is about 1129.5134859728.

Adding to 1441034113 its reverse (3114301441), we get a palindrome (4555335554).

The spelling of 1441034113 in words is "one billion, four hundred forty-one million, thirty-four thousand, one hundred thirteen".

Divisors: 1 59 24424307 1441034113