14410440442113 has 4 divisors (see below), whose sum is σ = 19213920589488. Its totient is φ = 9606960294740.

The previous prime is 14410440442031. The next prime is 14410440442127. The reversal of 14410440442113 is 31124404401441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14410440442113 - 2¹⁸ = 14410440179969 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14410440442313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2401740073683 + ... + 2401740073688.

It is an arithmetic number, because the mean of its divisors is an integer number (4803480147372).

Almost surely, 2^{14410440442113} is an apocalyptic number.

It is an amenable number.

14410440442113 is a deficient number, since it is larger than the sum of its proper divisors (4803480147375).

14410440442113 is an equidigital number, since it uses as much as digits as its factorization.

14410440442113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4803480147374.

The product of its (nonzero) digits is 24576, while the sum is 33.

Adding to 14410440442113 its reverse (31124404401441), we get a palindrome (45534844843554).

The spelling of 14410440442113 in words is "fourteen trillion, four hundred ten billion, four hundred forty million, four hundred forty-two thousand, one hundred thirteen".