144111320033 has 4 divisors (see below), whose sum is σ = 144126597120. Its totient is φ = 144096042948.

The previous prime is 144111320009. The next prime is 144111320063. The reversal of 144111320033 is 330023111441.

144111320033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 330023111441 = 6907 ⋅47780963.

It is a cyclic number.

It is not a de Polignac number, because 144111320033 - 2⁸ = 144111319777 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 144111319990 and 144111320008.

It is not an unprimeable number, because it can be changed into a prime (144111320063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7624385 + ... + 7643262.

It is an arithmetic number, because the mean of its divisors is an integer number (36031649280).

Almost surely, 2^144111320033 is an apocalyptic number.

It is an amenable number.

144111320033 is a deficient number, since it is larger than the sum of its proper divisors (15277087).

144111320033 is an equidigital number, since it uses as much as digits as its factorization.

144111320033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15277086.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 144111320033 its reverse (330023111441), we get a palindrome (474134431474).

The spelling of 144111320033 in words is "one hundred forty-four billion, one hundred eleven million, three hundred twenty thousand, thirty-three".