Base | Representation |
---|---|
bin | 1000011000110111010… |
… | …0011001000001011001 |
3 | 111202222111111020021221 |
4 | 2012031310121001121 |
5 | 4330120442222301 |
6 | 150112114532041 |
7 | 13261155230035 |
oct | 2061564310131 |
9 | 452874436257 |
10 | 144113242201 |
11 | 56133193965 |
12 | 23b1b297021 |
13 | 10788ab2716 |
14 | 6d91a1d1c5 |
15 | 3b36db4da1 |
hex | 218dd19059 |
144113242201 has 2 divisors, whose sum is σ = 144113242202. Its totient is φ = 144113242200.
The previous prime is 144113242199. The next prime is 144113242261. The reversal of 144113242201 is 102242311441.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 141842624400 + 2270617801 = 376620^2 + 47651^2 .
It is a cyclic number.
It is not a de Polignac number, because 144113242201 - 21 = 144113242199 is a prime.
Together with 144113242199, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (144113242261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72056621100 + 72056621101.
It is an arithmetic number, because the mean of its divisors is an integer number (72056621101).
Almost surely, 2144113242201 is an apocalyptic number.
It is an amenable number.
144113242201 is a deficient number, since it is larger than the sum of its proper divisors (1).
144113242201 is an equidigital number, since it uses as much as digits as its factorization.
144113242201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 144113242201 its reverse (102242311441), we get a palindrome (246355553642).
The spelling of 144113242201 in words is "one hundred forty-four billion, one hundred thirteen million, two hundred forty-two thousand, two hundred one".
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