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1441140403 is a prime number
BaseRepresentation
bin101010111100110…
…0000111010110011
310201102202111222111
41111321200322303
510422412443103
6355000350151
750466330343
oct12571407263
93642674874
101441140403
1167a53912a
12342775357
1319c754401
14d9580d23
15867be86d
hex55e60eb3

1441140403 has 2 divisors, whose sum is σ = 1441140404. Its totient is φ = 1441140402.

The previous prime is 1441140391. The next prime is 1441140409. The reversal of 1441140403 is 3040411441.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1441140403 is a prime.

It is a super-2 number, since 2×14411404032 = 4153771322318004818, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1441140409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 720570201 + 720570202.

It is an arithmetic number, because the mean of its divisors is an integer number (720570202).

Almost surely, 21441140403 is an apocalyptic number.

1441140403 is a deficient number, since it is larger than the sum of its proper divisors (1).

1441140403 is an equidigital number, since it uses as much as digits as its factorization.

1441140403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 22.

The square root of 1441140403 is about 37962.3550771024. The cubic root of 1441140403 is about 1129.5412560850.

Adding to 1441140403 its reverse (3040411441), we get a palindrome (4481551844).

The spelling of 1441140403 in words is "one billion, four hundred forty-one million, one hundred forty thousand, four hundred three".