14411520121 has 4 divisors (see below), whose sum is σ = 15170021200. Its totient is φ = 13653019044.

The previous prime is 14411520103. The next prime is 14411520191. The reversal of 14411520121 is 12102511441.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 12102511441 = 149 ⋅81224909.

It is a cyclic number.

It is not a de Polignac number, because 14411520121 - 2⁹ = 14411519609 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14411520092 and 14411520101.

It is not an unprimeable number, because it can be changed into a prime (14411520191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 379250511 + ... + 379250548.

It is an arithmetic number, because the mean of its divisors is an integer number (3792505300).

Almost surely, 2^14411520121 is an apocalyptic number.

It is an amenable number.

14411520121 is a deficient number, since it is larger than the sum of its proper divisors (758501079).

14411520121 is an equidigital number, since it uses as much as digits as its factorization.

14411520121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 758501078.

The product of its (nonzero) digits is 320, while the sum is 22.

The spelling of 14411520121 in words is "fourteen billion, four hundred eleven million, five hundred twenty thousand, one hundred twenty-one".