Base | Representation |
---|---|
bin | 10100111110001011100… |
… | …101001111100001111001 |
3 | 12002202212121222002112201 |
4 | 110332023211033201321 |
5 | 142102441343340441 |
6 | 3022020255110201 |
7 | 206056120344064 |
oct | 24761345174171 |
9 | 5082777862481 |
10 | 1441155840121 |
11 | 5062109a00a8 |
12 | 1b3380212361 |
13 | a5b9228b7aa |
14 | 4da764cd8db |
15 | 2774b35cc31 |
hex | 14f8b94f879 |
1441155840121 has 2 divisors, whose sum is σ = 1441155840122. Its totient is φ = 1441155840120.
The previous prime is 1441155840071. The next prime is 1441155840143. The reversal of 1441155840121 is 1210485511441.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1223813400121 + 217342440000 = 1106261^2 + 466200^2 .
It is a cyclic number.
It is not a de Polignac number, because 1441155840121 - 219 = 1441155315833 is a prime.
It is not a weakly prime, because it can be changed into another prime (1441155840151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 720577920060 + 720577920061.
It is an arithmetic number, because the mean of its divisors is an integer number (720577920061).
Almost surely, 21441155840121 is an apocalyptic number.
It is an amenable number.
1441155840121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1441155840121 is an equidigital number, since it uses as much as digits as its factorization.
1441155840121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25600, while the sum is 37.
The spelling of 1441155840121 in words is "one trillion, four hundred forty-one billion, one hundred fifty-five million, eight hundred forty thousand, one hundred twenty-one".
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