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14412012151351 = 28151288299471
BaseRepresentation
bin1101000110111000111011…
…0111010110001000110111
31220000202220220110211121211
43101232032313112020313
53342111300102320401
650352441553222251
73015143045015023
oct321561667261067
956022826424554
1014412012151351
1146571111590a1
121749189861987
1380707c0bc949
1437b78bad3383
1519ed52167951
hexd1b8edd6237

14412012151351 has 4 divisors (see below), whose sum is σ = 14463300451104. Its totient is φ = 14360723851600.

The previous prime is 14412012151349. The next prime is 14412012151357. The reversal of 14412012151351 is 15315121021441.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14412012151351 - 21 = 14412012151349 is a prime.

It is a super-2 number, since 2×144120121513512 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14412012151357) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25644149455 + ... + 25644150016.

It is an arithmetic number, because the mean of its divisors is an integer number (3615825112776).

Almost surely, 214412012151351 is an apocalyptic number.

14412012151351 is a deficient number, since it is larger than the sum of its proper divisors (51288299753).

14412012151351 is an equidigital number, since it uses as much as digits as its factorization.

14412012151351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51288299752.

The product of its (nonzero) digits is 4800, while the sum is 31.

Adding to 14412012151351 its reverse (15315121021441), we get a palindrome (29727133172792).

The spelling of 14412012151351 in words is "fourteen trillion, four hundred twelve billion, twelve million, one hundred fifty-one thousand, three hundred fifty-one".

Divisors: 1 281 51288299471 14412012151351