Base | Representation |
---|---|
bin | 100000110001001110100111… |
… | …000010101011011000100111 |
3 | 200220021210000120102220222122 |
4 | 200301032213002223120213 |
5 | 122342232120102124333 |
6 | 1230304002300220155 |
7 | 42233233416262244 |
oct | 4061164702533047 |
9 | 626253016386878 |
10 | 144120430114343 |
11 | 41a15149651231 |
12 | 141b760853a65b |
13 | 6255662849b07 |
14 | 2783674b365cb |
15 | 119dd830ad798 |
hex | 8313a70ab627 |
144120430114343 has 4 divisors (see below), whose sum is σ = 144120465906768. Its totient is φ = 144120394321920.
The previous prime is 144120430114319. The next prime is 144120430114361. The reversal of 144120430114343 is 343411034021441.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 144120430114343 - 26 = 144120430114279 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (144120430114303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10960346 + ... + 20208167.
It is an arithmetic number, because the mean of its divisors is an integer number (36030116476692).
Almost surely, 2144120430114343 is an apocalyptic number.
144120430114343 is a deficient number, since it is larger than the sum of its proper divisors (35792425).
144120430114343 is an equidigital number, since it uses as much as digits as its factorization.
144120430114343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35792424.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 144120430114343 its reverse (343411034021441), we get a palindrome (487531464135784).
The spelling of 144120430114343 in words is "one hundred forty-four trillion, one hundred twenty billion, four hundred thirty million, one hundred fourteen thousand, three hundred forty-three".
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