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14412055544197 is a prime number
BaseRepresentation
bin1101000110111001000101…
…1100111000000110000101
31220000210000221010102102021
43101232101130320012011
53342111342204403242
650352450143243141
73015144112603543
oct321562134700605
956023027112367
1014412055544197
1146571336a6853
1217491a02a94b1
138070880a389c
1437b79378ad93
1519ed55d89b67
hexd1b91738185

14412055544197 has 2 divisors, whose sum is σ = 14412055544198. Its totient is φ = 14412055544196.

The previous prime is 14412055544119. The next prime is 14412055544207. The reversal of 14412055544197 is 79144555021441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13828238825956 + 583816718241 = 3718634^2 + 764079^2 .

It is a cyclic number.

It is not a de Polignac number, because 14412055544197 - 27 = 14412055544069 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14412055044197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7206027772098 + 7206027772099.

It is an arithmetic number, because the mean of its divisors is an integer number (7206027772099).

Almost surely, 214412055544197 is an apocalyptic number.

It is an amenable number.

14412055544197 is a deficient number, since it is larger than the sum of its proper divisors (1).

14412055544197 is an equidigital number, since it uses as much as digits as its factorization.

14412055544197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4032000, while the sum is 52.

The spelling of 14412055544197 in words is "fourteen trillion, four hundred twelve billion, fifty-five million, five hundred forty-four thousand, one hundred ninety-seven".