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14412055544713 is a prime number
BaseRepresentation
bin1101000110111001000101…
…1100111000001110001001
31220000210000221010110010101
43101232101130320032021
53342111342204412323
650352450143245401
73015144112605211
oct321562134701611
956023027113111
1014412055544713
1146571336a7182
1217491a02a9861
138070880a3ba8
1437b79378b241
1519ed55d89dad
hexd1b91738389

14412055544713 has 2 divisors, whose sum is σ = 14412055544714. Its totient is φ = 14412055544712.

The previous prime is 14412055544699. The next prime is 14412055544759. The reversal of 14412055544713 is 31744555021441.

It is an a-pointer prime, because the next prime (14412055544759) can be obtained adding 14412055544713 to its sum of digits (46).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14326807895929 + 85247648784 = 3785077^2 + 291972^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14412055544713 is a prime.

It is a super-4 number, since 4×144120555447134 (a number of 54 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (14412055044713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7206027772356 + 7206027772357.

It is an arithmetic number, because the mean of its divisors is an integer number (7206027772357).

Almost surely, 214412055544713 is an apocalyptic number.

It is an amenable number.

14412055544713 is a deficient number, since it is larger than the sum of its proper divisors (1).

14412055544713 is an equidigital number, since it uses as much as digits as its factorization.

14412055544713 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1344000, while the sum is 46.

The spelling of 14412055544713 in words is "fourteen trillion, four hundred twelve billion, fifty-five million, five hundred forty-four thousand, seven hundred thirteen".