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14412141111 = 34804047037
BaseRepresentation
bin11010110110000011…
…11101001000110111
31101012101222121220010
431123001331020313
5214004002003421
610342034111303
71020101115054
oct153301751067
941171877803
1014412141111
116126306a25
12296271b533
131488b11764
149aa11c02b
155953e4076
hex35b07d237

14412141111 has 4 divisors (see below), whose sum is σ = 19216188152. Its totient is φ = 9608094072.

The previous prime is 14412141103. The next prime is 14412141127. The reversal of 14412141111 is 11114121441.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 14412141111 - 23 = 14412141103 is a prime.

It is a super-2 number, since 2×144121411112 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14412141131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2402023516 + ... + 2402023521.

It is an arithmetic number, because the mean of its divisors is an integer number (4804047038).

Almost surely, 214412141111 is an apocalyptic number.

14412141111 is a deficient number, since it is larger than the sum of its proper divisors (4804047041).

14412141111 is an equidigital number, since it uses as much as digits as its factorization.

14412141111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4804047040.

The product of its digits is 128, while the sum is 21.

Adding to 14412141111 its reverse (11114121441), we get a palindrome (25526262552).

The spelling of 14412141111 in words is "fourteen billion, four hundred twelve million, one hundred forty-one thousand, one hundred eleven".

Divisors: 1 3 4804047037 14412141111