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144122400535 = 5678910874447
BaseRepresentation
bin1000011000111001011…
…1010100111100010111
3111210000010201112011111
42012032113110330113
54330130313304120
6150113043115451
713261326122521
oct2061627247427
9453003645144
10144122400535
1156138379733
1223b22372b87
131078a96b159
146d92d24a11
153b37ac375a
hex218e5d4f17

144122400535 has 32 divisors (see below), whose sum is σ = 177703649280. Its totient is φ = 112172366592.

The previous prime is 144122400533. The next prime is 144122400547. The reversal of 144122400535 is 535004221441.

It is a cyclic number.

It is not a de Polignac number, because 144122400535 - 21 = 144122400533 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 144122400497 and 144122400506.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (144122400533) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 32406682 + ... + 32411128.

It is an arithmetic number, because the mean of its divisors is an integer number (5553239040).

Almost surely, 2144122400535 is an apocalyptic number.

144122400535 is a deficient number, since it is larger than the sum of its proper divisors (33581248745).

144122400535 is a wasteful number, since it uses less digits than its factorization.

144122400535 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5695.

The product of its (nonzero) digits is 19200, while the sum is 31.

Adding to 144122400535 its reverse (535004221441), we get a palindrome (679126621976).

The spelling of 144122400535 in words is "one hundred forty-four billion, one hundred twenty-two million, four hundred thousand, five hundred thirty-five".

Divisors: 1 5 67 89 335 445 1087 4447 5435 5963 22235 29815 72829 96743 297949 364145 395783 483715 1489745 1978915 4833889 6481781 24169445 26517461 32408905 132587305 323870563 430216121 1619352815 2151080605 28824480107 144122400535