Base | Representation |
---|---|
bin | 1000011000111001011… |
… | …1010100111100010111 |
3 | 111210000010201112011111 |
4 | 2012032113110330113 |
5 | 4330130313304120 |
6 | 150113043115451 |
7 | 13261326122521 |
oct | 2061627247427 |
9 | 453003645144 |
10 | 144122400535 |
11 | 56138379733 |
12 | 23b22372b87 |
13 | 1078a96b159 |
14 | 6d92d24a11 |
15 | 3b37ac375a |
hex | 218e5d4f17 |
144122400535 has 32 divisors (see below), whose sum is σ = 177703649280. Its totient is φ = 112172366592.
The previous prime is 144122400533. The next prime is 144122400547. The reversal of 144122400535 is 535004221441.
It is a cyclic number.
It is not a de Polignac number, because 144122400535 - 21 = 144122400533 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 144122400497 and 144122400506.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (144122400533) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 32406682 + ... + 32411128.
It is an arithmetic number, because the mean of its divisors is an integer number (5553239040).
Almost surely, 2144122400535 is an apocalyptic number.
144122400535 is a deficient number, since it is larger than the sum of its proper divisors (33581248745).
144122400535 is a wasteful number, since it uses less digits than its factorization.
144122400535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5695.
The product of its (nonzero) digits is 19200, while the sum is 31.
Adding to 144122400535 its reverse (535004221441), we get a palindrome (679126621976).
The spelling of 144122400535 in words is "one hundred forty-four billion, one hundred twenty-two million, four hundred thousand, five hundred thirty-five".
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