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144124041551 = 720589148793
BaseRepresentation
bin1000011000111001110…
…1100101100101001111
3111210000020210220012212
42012032131211211033
54330131223312201
6150113142221035
713261346066030
oct2061635454517
9453006726185
10144124041551
115613929a646
1223b22a2477b
131078b0c4079
146d93230a87
153b37ce9abb
hex218e76594f

144124041551 has 4 divisors (see below), whose sum is σ = 164713190352. Its totient is φ = 123534892752.

The previous prime is 144124041541. The next prime is 144124041553. The reversal of 144124041551 is 155140421441.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 155140421441 = 198165285339.

It is a cyclic number.

It is not a de Polignac number, because 144124041551 - 222 = 144119847247 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (144124041553) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10294574390 + ... + 10294574403.

It is an arithmetic number, because the mean of its divisors is an integer number (41178297588).

Almost surely, 2144124041551 is an apocalyptic number.

144124041551 is a deficient number, since it is larger than the sum of its proper divisors (20589148801).

144124041551 is an equidigital number, since it uses as much as digits as its factorization.

144124041551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20589148800.

The product of its (nonzero) digits is 12800, while the sum is 32.

Adding to 144124041551 its reverse (155140421441), we get a palindrome (299264462992).

The spelling of 144124041551 in words is "one hundred forty-four billion, one hundred twenty-four million, forty-one thousand, five hundred fifty-one".

Divisors: 1 7 20589148793 144124041551